Hello,
I have (I hope so) a simple question...
How do I create a link with an image?
The normal way is so:
The problem is the following:
The pictures I'd like to show are saved on my server, the path is saved in a mySQL-Database.
Here is the structure:
id int(11) auto_increment
picturenumber int(11) -> imagename on the server
gallery int(11) -> FK to another table (at the moment not relevant)
portfolio bool
How the pictures are stored:
server/gallery/[gallery]/[picturenumber].jpg
And now the big question...
What have I to insert in the server/protected/views/gallery/_view.php?
It must be something like this![;)]()
<?php echo CHtml::link(<img src="gallery/"$data->gallery/th_$data->picturenumber.jpg" alt="$data->picturenumber.jpg" />, array('view', 'id'=>$data->id)); ?>
And the output must be like this:
Thanks in advance!
I have (I hope so) a simple question...
How do I create a link with an image?
The normal way is so:
<?php echo CHtml::link([some HTML], array('view', 'id'=>$data->id)); ?>
The problem is the following:
The pictures I'd like to show are saved on my server, the path is saved in a mySQL-Database.
Here is the structure:
id int(11) auto_increment
picturenumber int(11) -> imagename on the server
gallery int(11) -> FK to another table (at the moment not relevant)
portfolio bool
How the pictures are stored:
server/gallery/[gallery]/[picturenumber].jpg
And now the big question...
What have I to insert in the server/protected/views/gallery/_view.php?
It must be something like this

<?php echo CHtml::link(<img src="gallery/"$data->gallery/th_$data->picturenumber.jpg" alt="$data->picturenumber.jpg" />, array('view', 'id'=>$data->id)); ?>
And the output must be like this:
<a href="server/index.php?r=pictures/view&id=[id]"> <img src="server/gallery/[$data->gallery]/[$data->picturenumber].jpg" alt="[$data->picturenumber]"> </a>
Thanks in advance!
